A body loses half of its velocity on penetrating 6 cm in a wooden block. how much will it penetrate more before coming to rest
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let u be the initial speed
(u/2)² - (u)² = -2a (6)
since it loses half its speed after 6 cm
a = (u)²/16
let the total distance of penetration = x
so
0- (u)²= -2{(u)²/16}x
x=8 cm
so the additional penetration = 8-6 = 2 cm
(u/2)² - (u)² = -2a (6)
since it loses half its speed after 6 cm
a = (u)²/16
let the total distance of penetration = x
so
0- (u)²= -2{(u)²/16}x
x=8 cm
so the additional penetration = 8-6 = 2 cm
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