Question

A body m=2kg initially moving at 5m/s is acted upon by friction f=8n such that its speed decreases find final velocity of body if it is displaced by 2m.

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Answer 1

Given:-

• Mass of Body = 2kg

• Initial velocity of body = 5m/s

• Force acting = - 8N

• Displacement = 2m

To Find:-

• The Final velocity of body.

Formulae used:-

• F = ma
• v² - u² = 2as

Where,

• F = Force
• m = Mass
• a = Acceleration
• v = Final velocity
• u = Initial velocity
• s = Distance

Now,

→ F = ma

→ 8 = 5 × a

→ 8 = 5a

→ a = 8/5

→ a = -1.6m/s²

Therefore,

→ v² - u² = 2as

→ v² - (5)² = 2 × 1.6 × 2

→ v² - 25 = 6.4

→ v² = 6.4 + 25

→ v² = 18.4

→ v = 4.3m/s

Thus, It's Final velocity is 4.3m/s.

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

A body m=2kg initially moving at 5m/s is acted upon by friction f=8n such that its speed decreases find final velocity of body if it is displaced by 2m.

$\huge{\boxed{\rm{\red{Answer}}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Mass of the body = 2 kg.

• Force acting = -8N.

• Displacement = 2 m.

• Body's initial velocity = 5m/s.

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• Body's final velocity.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• Body's final velocity = 4.3 m/s

$\large{\boxed{\boxed{\sf{What \: the \: question \: say\: ?}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: question \: 1{st}}}}}$

• The question says that there is a body of mass 2 kg , initial velocity of body which is moving at 5m/s . Now there is a friction acted upon it of 8N . Then the sped is decreased. Now we have ask to find the final velocity of the body if the displaced by 2 metres.

$\large{\boxed{\boxed{\sf{How \: to \: do \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Procedure \: of \: the \: question \: is \: given \: below}}}}$

• In this question we have to use formula to find force firstly. And we know that formula to find force is F = ma. After that we have to put the values according to the formula. We have done. After that we find our first result that is 16 m/s² . Now we have to use the formula to find final velocity . We know that what's the formula to find final velocity. The formula is v² - u² = 2as. Putting the values according to the formula we get our final result that is 4.3 m/s . Hence, the final velocity is finded by us.

$\large{\boxed{\boxed{\sf{Let's \: solve \: it \: properly}}}}$

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

$\large\purple{\texttt{According to the question}}$

$\large\purple{\texttt{Formulas are given below}}$

$\bold{\pink{\fbox{\green{F = ma}}}}$

$\bold{\pink{\fbox{\green{v² - u² = 2as}}}}$

$\large\underbrace\mathfrak\blue{Meaning \: of \: formula's \: term}$

❍ $\large\pink{\texttt{F means force}}$

❍ $\large\pink{\texttt{m means mass of object}}$

❍ $\large\pink{\texttt{a means acceleration}}$

❍ $\large\pink{\texttt{v means final velocity}}$

❍ $\large\pink{\texttt{u means initial velocity}}$

❍ $\large\pink{\texttt{s means distance}}$

$\large\red{\texttt{Note :}}$ The terms like m , a , v , u , s are written small. And F is written big.

$\large\red{\texttt{Because :}}$ We have to write these values according to the formulas.

$\large\purple{\texttt{Coming to the question}}$

$\large\purple{\texttt{Let's carry on}}$

$\large\orange{\texttt{We know F = ma}}$

$\large\underbrace\mathfrak\blue{Putting \: the \: values \: we \: get}$

$\large\purple{\texttt{Now,}}$

$\leadsto$ F = ma

$\leadsto$ 8 = 5 × a {Given values}

$\leadsto$ 8 = 5a

$\leadsto$ a = 8/5 { × = ÷ }

$\leadsto$ a = 1.6 m/s²

$\large\orange{\texttt{We know v² - u² = 2as}}$

$\large\underbrace\mathfrak\blue{Putting \: the \: values \: we \: get}$

$\large\purple{\texttt{Therefore}}$

$\leadsto$ v² - (5)² = 2 × 1.6 × 2

$\leadsto$ v² - 25 = 6.4

$\leadsto$ v² = 6.4 + 25 { - = + }

$\leadsto$ v² = 18.4

$\leadsto$ v = √18.4 {² = √ )

$\leadsto$ v = 4.3 m/s

$\large{\boxed{\boxed{\underline{\underline{\sf{4.3 \: m/s}}}}}}$

Hope it's helpful

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