Question

A body makes shm with an amplitude 4 sec and time period 12 second along y axis. At what displacement is its velocity will be the same as the velocity at 2 seconds after crossing the mean position?

Answer 1

Answer:

Given, T = Time period A = AmplitudeThe equation of motion in S.H.M x = Asin(ω t) The particle reach to extreme position to A2 A2 = Asin(ω t)

Answer 2

The displacement is 3.4 m

The amplitude of the S.H.M. is (A) = 4 m

The time period of the S.H.M. is (T) = 12 s

Given time is = 2 s which is 1/6 th of the time period, i.e., T/6

At T/6, the particle's position can be = √3 A/2

So, the position can be = √3 × 4/2 m

                                       = 3.4 m

The displacement at which its velocity will be the same as the velocity at 2 seconds after crossing the mean position is 3.4 m.