a body mass 5kg,initially at rest,is moved by a force of 2N on smooth horizontal surface . the work done by the force in 10s is ......
Answers
Answered by
8
Answer:
w=40 J
Explanation:
A=F/m
a=2/5 m/s²
s=1/2at² ( because u is zero)
s=1/2*2/5*10²
s=2/10*100
s=20m
w=F.S
w=2*20
w=40 J
Answered by
4
Answer:
40J
Explanation:
A=F/m
a=2/5 m/s²
s=1/2at² ( because u is zero)
s=1/2*2/5*10²
s=2/10*100
s=20m
w=F.S
w=2*20
w=40 J
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