Question

a body move from rest with uniform acceleration and travels 27 km in 3 seconds find the velocity of the body at 10sec second from the start.

Answer 1

s=ut+1/2at^2
27000=1/2 × a ×9
a=6000m/s

now
V=ut+at
=6000×10
=60000m/s
=60km/s

Answer 2

 s=ut + 1/2 at^{2} from this equation we will find 
   1/2 at2 = s-ut 
  a= 2(s-ut)/t2
  here initial speed u=0 so ut = 0
  a= 2*270/3*3 
  a = 60m/s2 - (1)
  Now we know that v= u+at
from eqn 1 a= 60m/s2
 so here v= 0+ 60*10
 v=600m/s

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