Question

A body move with initial velocity of 2m/s and uniform acceleration of 3m/s sqaure Calculate velocity when it has travelled a distance of 77 m

Answer 1

Hello,


The initial velocity = 2 m/sec

Uniform Acceleration = 3 m/sec²

Distance covered = 77m


From the equations of motion :-

We know that :-

2as = v²-u²
V² = 2as + u²
V² = 2*3*77+(2)²
V²=462+4=466

$v = \sqrt{466}$
So,

Final velocity = root466 m/sec


Hope this will be helping you.......

Answer 2

Answer:

Here,u=2m/s

S= 77m

accl^n=3m/s

V^2=u^2+2as

= (2)^2 + 2×3×77m

= 4 + 462

V^2= 466

V = root466

V = 22.33 m/s

Explanation:Hope u understand it....