Question

A body moves 12 metre due east and then threw 5 metre due north, what is the magnitude of his net displacement?​

Answer 1

Answer:

Net displacement= 13 m.

Explanation:   Displacement is the shortest distance between its final and initial point.

By pythagoras theorem-- hyp^2= leg^2 + leg^2

HERE, Hypoteuse is the displacement

Therefore, hyp^2= 12^2+5^2

hyp^2= 144+25

hyp^2=169

→→hyp=√169

∴ hypotenuse= 13

We said earlier that the hypotenuse here is equal to the displacement to be found..

Therefore,, displacement shall be 13 m