Physics, asked by shivi4221, 1 year ago

A body moves 6 m norin, 8 m east and 10 m vertically upwards, the resultant displacement of body from its
intial position is​

Answers

Answered by Anonymous
1

Hii its tom85

6m north and 8m east

by Pythagoreas theorem

s= h = sqrt 8^2 +6^2 =sqrt100 =10m

another is upward =10m

displacement = sqrt10^2 +10^2 =sqrt 200= 10sqrt2

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Hope it may helps you

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