Question

 A body moves 6 m North. 8 m East and 10m vertically upwards, what is its resultant displacement from initial position? 

Answer 1

10√2 m.
It involves 2 triangles on which you will need to apply the Vector addition by Triangle method.
First on 6m and 8m giving resultant 10m and then initial position to final position in upward direction which too is 10m up from the last point which we got by vector addition.
So answer is 10√2 m.

Answer 2

"The final displacement of the body is 14.14 m from the initial position.

Given:

Let the vertical y axis represent North and the horizontal x axis represent East. Let the z axis represent the vertically upward direction.

X axis component, x = 8

Y axis component, y = 6

Z axis component, z = 10

Final displacement, d = ?

Solution:

The final displacement of a particle from origin is given by

$d=\sqrt{x^{2}+y^{2}+z^{2}}$

On substituting,

$d=\sqrt{8^{2}+6^{2}+10^{2}}$

$=\sqrt{64+36+100}$

d = 14.14 m"