A body moves 6 m north .8 m east and 10m vertically upwards . what is the magnitude of its resultant displacement from initial position
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Case i-
Given: -
IA = 6m
AO=8m
According to Pythagoras theorem,
IO=√{(6*6)+(8*8)}
=√36+64
=√100
=10
Case ii: -
Given: -
IO=10
OF=10
So, According to Pythagoras theorem,
IF=√(10*10+10*10)
=√(100+100)
=√200
=14.14(approx.)
Therefore, Displacement is 14.14m
Given: -
IA = 6m
AO=8m
According to Pythagoras theorem,
IO=√{(6*6)+(8*8)}
=√36+64
=√100
=10
Case ii: -
Given: -
IO=10
OF=10
So, According to Pythagoras theorem,
IF=√(10*10+10*10)
=√(100+100)
=√200
=14.14(approx.)
Therefore, Displacement is 14.14m
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