Question

A body moves 6m north..8 m east and 10 m vertically upward..what is its resultant displacement from initial position(only magnitude)
1....10 under root 2m
2....10 m
3...10/under root 2m
4...10×2m

Answer 1

Answer:

Correct option is A)

Consider, east direction to be x-direction, north direction to be y-direction and vertically upward direction to be z-direction.

Displacement of the particle is given by    

S

=8

i

^

+6

j

^

​

+10

k

^

Magnitude of displacement  ∣

S

∣=

6

2

+8

2

+10

2

​

=10

2

​

 m

Explanation:

Answer 2

Explanation:

4...10×2m

Solution

Consider, east direction to be x-direction, north direction to be y-direction and vertically upward direction to be z-direction.

Displacement of the particle is given by

S

=8

i

^

+6

j

^

+10

k

^

Magnitude of displacement ∣

S

∣=

6

2

+8

2

+10

2

=10

2

m

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