A body moves 6m north. 8m east and 10m vertically upwards, Find the resultant displacement of the body from initial position.
Answers
It will be triangle of side 16m and 8m
Shortest distance is called displacement and is the hypotenuse is the triangle
So answer will be 17.8
Kindly mark as brainliest and feel free to ask for any clarification
GIVEN :-
A boy move 6 m north 8 m east and 10 m vertically upwards.
TO FIND :-
The resultant displacement from the initial position.
PRE-REQUISITE :-
Displacement is the shortest length between the initial position and the final position.
OR
Displacement is the change in position vector.
SOLUTION :-
If a body moves 6 m North, 8 m East and 10 m vertically upwards then its resultant displacement from initial position will be in the form of a cuboid with length 6 m, breadth 8 m and height 10 m.
And the resultant displacement would be the diagonal of this cuboid.
So, the diagonal of a cuboid :-
√(6²+8²+10²)
= √200
= √(100 × 2)
= 10√2
∴ So, the displacement of the boy from his initial position is 10√2 units.