Question

a body moves a distance 10m along a straight line under the action of a force of 5N, if the work done is 25J , the angle which the force makes with the direction of the motion--a)0° b) 30° c) 60°​

Answer 1

Answer:

correct option is (c) ...

Explaination

$w = fs \cosΘ$

$\cosΘ = \frac{w}{fs} = \frac{25}{10 \times 5 } = \frac{1}{2}$

$\cos(60) = \frac{1}{2}$

so your answer is 60° .......

Answer 2

Answer:

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GIVEN :-

Displacement :- 10 m

Force = 5N

work done = 25 J

Formula used :-

Work done =

$f.d \cos( \alpha )$

CALCULATION :-

25 J = 5× 10 ×COS (alpha)

so,

cos (alpha) = 25/50

hence,

Cos (alpha) = 1/2.

then Required Angle = 60°. ( Ans).

so, correct Option = (C)

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