Question

A body moves along a straight line with acceleration 3 m/sec2

for 2 seconds and then with

acceleration 4 m/sec2

for 3 sec. What is the average acceleration.​

Answer 1

Answer:

2.57

Explanation:

Average acceleration

= ∆v / ∆t

= (3×2+4x3)/(4+3)

= 18/7

= 2.57 m/s2

Answer 2

Answer:-

$\bold{a_{avg} = 3.6 m{s}^{-2}}$

Explanation:-

Given:-

• $a_1 = 3m{s}^{-2}$
• $a_2 = 4 m{s}^{-2}$
• $t_1 = 2 sec$
• $t_2 = 3 sec$

To Find:-

Average Acceleration

Solution:-

w.k.t,

$a_{avg} = \dfrac{\delta v}{\delta t}$

$a_{avg} = \dfrac{a_1t_1+ a_2t_2}{t_1+t_2}$

$a_{avg} = \dfrac{3 \times 2 + 4 \times 3}{3+2}$

$a_{avg} = \dfrac{6 + 12}{5}$

$a_{avg} = \dfrac{18}{5}$

$\bold{a_{avg} = 3.6 m{s}^{-2}}$