Question

A body moves along a straight line with uniform acceleration. The body
covers a distance of 18 m in the first three seconds and 22 m in the next
5 seconds
(1) What is the velocity at the end of 10 seconds ?
(ii) What is the distance covered in 10th second ?​

Answer 1

Answer:

(i) 50 m/s

(ii) 500 m

Explanation:

(i) Given

D1= 18 m

t1 = 3 s

D2 = 22 m

t2 = 5 s

we know that

Average Accelartion = (D1 + D2)/(t1 + t2)

=> Av. Acc. = (18 + 22)/(3 + 5)

=> Av. Acc. = 40/8

=> Av. Acc. = 5 m/s^2

Now, We find velocity at end of 10 seconds :

We know that

Acc. = (v - u)/t

=> 5 = (v-0)/10

=> 5 = v/10

=> v = 5 × 10 = 50 m/s

(ii)

let the distance covered in 10th second = d

We know that

v = d/t

=> 50 = d/10

=> d = 500 m