Question

a body moves along the circumference of a circular track of radius R and completes 1 round in 20 seconds. What will be the distance and displacement at the end of 1 minute 10 seconds.​

Answer 1

Answer:

Distance = 11 R ^ 2

Displacement = 2R

Explanation:

Answer 2

Given:

A body moves along the circumference of a circular track of radius R and completes 1 round in 20 seconds.

To find:

Distance and displacement at the end of 1 min 10 sec.

Calculation:

Total time of travel = 1 min + 10 sec = 70 sec.

Now , in this time , total number of revolutions in the circular track :

$\sf{ \therefore \: no. \: of \: revolutions = \dfrac{70}{20} = 3.5}$

So, the object will cover 3 full revolutions and one ½ revolution after 70 secs.

So, net distance be d1 :

$\sf{ \therefore \: d1 = 3.5 \times (2\pi R)}$

$\boxed{ \sf{ = > \: d1 = 7\pi R}}$

Now , after 70 secs , the object will be at a diametrically opposite position from the starting point.

Let displacement be d2 :

$\boxed{ \sf{ \therefore \: d2 = 2R}}$

HOPE IT HELPS.