Question

A body
moves
distance
0
of 18m
along a straught line with uniform
acceleration. The body covers
in the first three seconds and am in the
next s seconds.
1. What is
the vedcity at the end of 10 second?
10th second.
)
What is
the
covered in
gomil​

Answer 1

Answer:

u=0,s=270m,t=3s

s=ut+ 1/2at^2

270=0×3+1/2×a×3^2

a=60 m/s^2

Now putting the value of a in v=u+at,

Velocity after t=10s is given by

v=0+60×10=600 m/s