Question

A body moves for 3 seconds with a constant acceleration during which
time it describes 24.30 m: the acceleration then ceases and during the
next 3 seconds it describes 21.60 m; find its initial velocity and
acceleration.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

u=9.1m/s,a=-0.6m/s^-2

Step-by-step explanation:

let, acceleration=a initial velocity=u

in first case,

t=3 sec

s=24.30m

then,

s=ut+1/2at^2

24.30=3u+1/2a×9

24.30=3u+4.5a....(ll)

in case second

a=0. (acceleration ceases)

s=21.60m

u=u+3a

then,

21.60=(u+3a)3+0.5×0×9

21.60=3u+9a....(ll)

solving(I) and (ll)

a=-0.6 and u=9