Question

A body moves from A to B at a speed of 10m/s and back to A along the same path at a speed of 20m/s. find it's average speed and average velocity for the journey

Answer 1

Answer:

Average speed is the distance traveled divided by the time taken to travel …

Each leg of the journey is the same distance, call it d = |AB| (that is just maths-speak for “d is the distance from A to B”).

We are not told directly what it is… the trick with this sort of question is to just use variables for the things you don’t know and hope it all comes out OK at the end. So keep on going and just put d everywhere we’d normally want to have the actual distance.

The total distance traveled is 2d because the body does goes over the same ground twice.

The time on the first leg of the journey is d/10, and for the second part is d/20 (in seconds).

So the total time is d/10 + d/20 = 30d/200

So the average speed is distance over time:

v¯=2d30d/200=(40/3)m⋅s−1

The second part is a trick question, sort of.

The average velocity is the total displacement divided by the total time.

Displacement is a vector … it’s the change in position.

Since the body returns to the same position it started out in, it does not change position overall, so it’s total displacement is zero. Therefore the average velocity is zero....

I HOPE I AM HELP TO YOU

PLEASE FOLLOW ME

Answer 2

Average speed is defined as the total distance covered divided by the total time taken.

Let the distance between A and B be x.

Time for foward trip = T

Time for return trip = T’

Therefore,

Avg. Speed = (x+x)/(T+T’)= 2x/T+T’ ————— (1)

Now we can write T and T’ in terms for velocity and distance

T = x/10

T’= x/20

Substituting back in (1)

Avg. Speed = 2x/(x/10) + (x/20)

= (2x×20)/3x= 40/3 m/s

Average velocity

Average velocity is the total displacement divided by total time.

Here displacement is zero hence Avg. VELOCITY =0

Explanation:

hope it helps you

pls mark as brainliest