Question

A body moves, from rest with a constant acceleration of . The 3m/s2distance covered in 5 sec. Is

Answer 1

$\Large\underline{\underline{\sf \orange{Given}:}}$

• Initial Velocity (u) = 0 m/s

• Acceleration of body (a) = 3m/s²

• Time (t) = 5sec

$\Large\underline{\underline{\sf \orange{To\:Find}:}}$

• Distance covered (s) = ?

$\Large\underline{\underline{\sf \orange{Formula\:Used}:}}$

$\large{\boxed{\sf \red{s=ut+\dfrac{1}{2}at^2 }}}$

$\Large\underline{\underline{\sf \orange{Solution}:}}$

$\large\implies{\sf s=ut+\dfrac{1}{2}at^2}$

$\implies{\sf s=0×5+\dfrac{1}{2}×3×5^2}$

$\implies{\sf s=0+\dfrac{1}{2}×3×25 }$

$\implies{\sf s=\dfrac{1}{2}×75 }$

$\implies{\sf s=37.5\:m}$

$\Large\underline{\underline{\sf \orange{Answer}:}}$

⛬ Distance covered by body is 37.5m

Answer 2

Answer:

Given:

Initial Velocity = 0 m/s

Acceleration = 3 m/s²

Time = 5 sec.

To find:

Distance covered in 5 seconds

Formulas used:

S = ut + ½at²

Calculation:

Putting the values of "u" , "t" and "a",

we get:

S = ut + ½at²

=> S = (0 × 5) + (½ × 3 × 5²)

=> S = ½ × 3 × 25

=> S = 37.5 metres.