A body moves from rest with a uniform acceleration 5 ms-2. After 10 s what will be its velocity?
(i) 5 ms-1
(ii) 25 ms-1
(iii) 20 ms-1
(iv) 50 ms-1
please answer me fast
Answers
Answered by
11
Answer:
50ms
Explanation:
initial velocity =0
a=5ms^2
t=10s
v=u+at
v=0+5*10
v=50ms
Answered by
35
Given
- Body starts from rest so, Initial velocity of body, u = 0
- Body moves with uniform acceleration, a = 5 m/s²
To find
- Velocity of body after time 't = 10 s'; v = ?
Formula required
- First equation of motion
v = u + a t
[ Where
v = final velocity
u = initial velocity
t = time taken
a = acceleration ]
Solution
Using first equation of motion
→ v = u + a t
putting known values
→ v = ( 0 ) + ( 5 ) ( 10 )
→ v = 0 + 50
→ v = 50 m/s
Therefore,
- Velocity of body after time 10 s will be 50 m/s.
Three equations of motion
- First equation of motion
v = u + a t
- Second equation of motion
s = u t + 1/2 a t²
- Third equation of motion
2 a s = v² - u²
[ Where v = final velocity, u = initial velocity, t = time taken, a = acceleration, s = distance covered ]
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