Question

A body moves from rest with a uniform acceleration and travels 270m in 3s. Find the velocity and the acceleration of body

Answer 1

Given :

• Initial Velocity (u) = 0m/s
• Distance Travelled (s) = 270m
• Time Taken (t) = 3 sec.

To Find :

• Acceleration (a)
• Final Velocity (v)

Solution :

For Acceleration :

Using 2nd Equation :

$\longmapsto\tt\boxed{s=ut+\dfrac{1}{2}{at}^{2}}$

Putting Values :

$\longmapsto\tt{270=0(3)+\dfrac{1}{2}a{(3)}^{2}}$

$\longmapsto\tt{270\times{2}=0+9a}$

$\longmapsto\tt{540=9a}$

$\longmapsto\tt{a=\cancel\dfrac{540}{9}}$

$\longmapsto\tt\bold{a=60{m/s}^{2}}$

So , The Accerelation of the body is 60m/s²..

Now ,

For Final Velocity :

Using 1st Equation :

$\longmapsto\tt\boxed{v=u+at}$

Putting Values :

$\longmapsto\tt{v=0+60\times{(3)}}$

$\longmapsto\tt\bold{v=180m/s}$

So , The Final Velocity of the body is 180m/s..

Answer 2

Answer:

velocity = 270/3 = 90 m/s( velocity = displacement/time taken)

acceleration=90/3= 30m/s²(acceleration= velocity/time taken)