Question

a body moves from rest with a uniform acceleration of 470 cm in 6 seconds find its final velocity after 15 seconds​

Answer 1

Explanation:

Given :

Initial velocity (u) = 0 m/s.

Distance (s) = 470

Time (t) = 6 secs.

To find:

Acceleration (a) =?

Velocity after 15. sec

Solution :

We will use third equation of motion here;

s = ut + 1/2 at²

→ 270. 0 * 6+1/2 * a * 6 * 6

→ 470 =. 36/2 a

→ 36 a = 940

⇒a= 940/36

⇒a= 26 m/ s

Now,

We will use first equation of motion here;

After 15 secs.

V = u+ at

v. = 0+ 26 * 15

v= 390

v= 390 m/s

Hence,

The final velocity acquired by the car is 390 m/s

hope it helps you