A body moves from rest with uniform accelerating and travels 90meter in the fifth seconds. Calculate velocity of the body 10seconds after starting
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Answer:
72m/s
Explanation:
initial velocity=0( body was at rest)
time=5 sec
distance=90
from equation of motion
distance = initial velocity*time+1/2* acceleration*(time)²
90 = 0*5+ 1/2*acc.*5*5
90*2/25= acceleration
36/5 = acceleration
from equation of motion
final velocity= intial velocity+ acc.*t
final velocity= 36/5*10
final velocity= 72
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