Question

A body moves from rest with uniform acceleration and travels 270 in the fifth second .Find the velocity of the body at 10 seconds after the start.​

Answer 1

Answer:

a = 10.8 m/s²

v = 108 m/s

Step-by-step explanation:

Hey mate !

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Given :

Initial velocity (u) = 0 m/s.

Distance (s) = 270 m.

Time (t) = 5 secs.

To find :

Acceleration (a) =?

Velocity after 10 sec.

Solution :

We will use third equation of motion here;

s = ut + 1 / 2 at²

270 = 0(5) + 1/2 * a * 100

270 = 50a

a = 270/50

a = 10.8 m/s²

Now,

We will use first equation of motion here ;

After 10 secs.

v = u + at

v = 0 + 10.8*10

v = 108 m/s

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