Question

A body moves from rest with uniform acceleration and travels 270 in the fifth second .Find the velocity of the body at 10 seconds after the start.​

Answer 1

Answer:

velocity of body will be 600m/s

Explanation:

S nth=u+a(2n-1)/2

by putting values as u=0

s=270

n=5

we can calculate a=60m/s²

now v=u+at

then value of v=600m/s