Question

A body moves from rest with uniform acceleration and travels 250 m in 5 s. Find the velocity of the body at 10 s after the start. ​

Answer 1

S O L U T I O N :

$\underline\orange{\bf{Given\::}}$

• Displacement, (S) = 250 m
• Time taken, (t) = 5 sec.
• Initial velocity, (u) = 0

$\underline\red{\bf{Explanation\::}}$

As we know that 2nd equation of motion;

$\boxed{\bf{S=ut + \frac{1}{2} at^{2}}}$

A/q

→ 250 = 0 × 5 + 1/2 × a × (5)²

→ 250 = 0 + 1/2 × a × 25

→ 250 = 0 + 25a/2

→ 250 = 25a/2

→ 500 = 25a

→ a = 500/25

→ a = 20 m/sec²

Now,

We will use the 1st equation of motion a/c to the given time;

Time, (t) = 10 sec.

$\boxed{\bf{v = u + at}}$

→ v = 0 + 20 × 10

→ v = 0 + 200

→ v = 200 m/sec.

Thus,

The final velocity of the body at 10 sec after start will be 200 m/sec.

Answer 2

$\huge\mathcal{\mid{\mid{\underline{\pink{Good\:Morning\:}}}{\mid{\mid}}}}$

Qᴜᴇsᴛɪᴏɴ ;-

⭐ A body moves from rest with uniform acceleration and travels 250 m in 5 s. Find the velocity of the body at 10 s after the start. 

$\huge{\orange{\boxed{\fcolorbox{lime}{aqua}{\pink{ANSWER}}}}}$

✔️ According to the question,

• u (initial velocity) = 0 m/s

• s (distance) = 250 m

• t = 5 s

✔️ We know that

$\red\checkmark\:\bf\blue{s~=~ut~+~\dfrac{1}{2}at^2}$

→ 250 = 0 × 5 + 1/2 × a × 5²

→ 250 = 0 + 25/2 × a

→ a = 250×2/25

→ a = 10 × 2

→ a = 20 m/s²

Again, we know that

$\pink\checkmark\:\bf\green{v~=~u~+~at}$

• t = 10 s

→ v = 0 + 20 × 10

→ v = 200 m/s