Question

a body moves from rest with uniform acceleration and travels 270 m in 3 seconds find the velocity of the body at 10 seconds from the start

Answer 1

u=0m/s
In 3 seconds the body travels 270m.
So, in one second distance =270/3=90m
So, In 10 seconds distance=90*10=900m
so, s=900m
t=10 seconds
$s = ut + \frac{1}{2} at {}^{2} \\ 900 = 0 \times 10 + \frac{1}{2} \times a \times 10 \times 10 \\ 900 = 0 + 50a \\ 50a = 900 \\ a = \frac{900}{50} = 18$
So, acceleration of the body is 18m/sec^2.
$v = u + at \\ = 0 + 18 \times 10 \\ = 180$
So, velocity of the body after 10 seconds is 180m/s.