Question

A body moves from rest with uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 seconds after the start
Also show the process

Answer 1

Hii...
Here is your answer..

Solution:-
Uniform Acceleration=0(as he starts from rest)
Distance=270m
Time=3sec
Acceleration=?

We'll find it by using equation,that is:-
$= > s = ut + \frac{1}{2} a {t}^{2} \\ = > 270= 0 \times 3 + \frac{1}{2} \times a \times {(3)}^{2} \\ = > 270 = 0 \times \frac{1}{2} \times a \times 9$
$= > a = \frac{270 \times 2}{9} \\ = > a = \frac{540}{9}$
$= > a = 60m$
Now,
Acceleration=60m/s
Final velocity after 10 sec=
$= > a = \frac{(v - u)}{t} \\ = > 60 = \frac{(v - 0)}{10}$
$= > v = 60 \times 10 \\ = > v = 600$
So,final velocity after 10 sec is 600m

Hope it helps uh...✌️✌️✌️

Answer 2

This is the answer of your Q