A body moves in a circle of radius 2R. What is the distance covered and displacement of the body after 2 complete rounds?
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Answered by
23
distance after 1 round=circumference of circle
=2πr
=2*22\7*2r
distance after 2 rounds=2(2πr)
=4πr
Displacement=0
as the body completed 2 whole circles and got back at the same position it started.
=2πr
=2*22\7*2r
distance after 2 rounds=2(2πr)
=4πr
Displacement=0
as the body completed 2 whole circles and got back at the same position it started.
Anonymous:
thanks
Answered by
5
Hola User __________________
Here is Your Answer .......!!!!!!!
___________________________
☆Actually welcome to the concept of the Kinematics of a body in the circular path.....
☆Basically if we see here ...the body is translating in a circular ..path ....
thus the Distance travelled by it will be the path covered by it from the initial to the final point .....
☆Distance travelled will be = 2pi (2R) + 2pi (2R) = 8piR...units..
☆Displacement will be in the form of Angual displacement ....represented by theta...
☆thus the displacememt of the body from the initial and final point will be....
= ZERO....
______________________________
Hope it helps u........☺✌〽⚓
Here is Your Answer .......!!!!!!!
___________________________
☆Actually welcome to the concept of the Kinematics of a body in the circular path.....
☆Basically if we see here ...the body is translating in a circular ..path ....
thus the Distance travelled by it will be the path covered by it from the initial to the final point .....
☆Distance travelled will be = 2pi (2R) + 2pi (2R) = 8piR...units..
☆Displacement will be in the form of Angual displacement ....represented by theta...
☆thus the displacememt of the body from the initial and final point will be....
= ZERO....
______________________________
Hope it helps u........☺✌〽⚓
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