Question

A body moves in a circle of radius 5 m with a speed of 5 ms–1

. Then it has

A : an acceleration of 5 ms–2

B : an acceleration varying with direction alone

1

(i) Only A is correct

(ii) Only B is correct

(iii) Both A and B are correct

(iv) Neither A nor B is correct.​

Answer 1

I dont know the Answer exactly but

it could be (iv)

Answer 2

From the given question the correct answer is (iii).

A and B both are correct.

As we know that,

Given,

Circle of radius 5 m

speed is 5 ms–1

so,

$v$ $= 5 m/s$

$a = \frac{v^{2} }{R}$

$a =$ acceleration

$v^{2}$ = velocity in m/s.

$R =$ the radius of the circle.

$= \frac{(5m/s)^{2} }{5m}$

$=5m/s^{2}$

Hence, acceleration changes direction only and its magnitude remains constant.