A body moves in a circle with increasing angular velocity at time t=6sec, the angular velocity is 27 radian'sec what is the radius of the circle when linear velocity is 81cm/s.
Answers
Answered by
20
Answer:
v = r x w
81= r 27
r = 81/27= 3 cm
Answered by
4
Therefore the radius of the circle is 0.03 m or 3 cm.
Given:
The angular velocity of the body = ω = 27 rad/s
Linear velocity of the particle = v = 81 cm/s
Time = 6 seconds
To Find:
The radius of the circle.
Solution:
The given question can be solved as shown below.
Let the radius of the circle be 'r'.
Given that,
The angular velocity of the body = ω = 27 rad/s
Linear velocity of the particle = v = 81 cm/s = 81 × 10⁻² m/s = 0.81 m/s
The relation between linear velocity and angular velocity can be stated as shown below,
⇒ Linear velocity (v) = Radius of the circle (r) × Angular velocity (ω)
⇒ v = r × ω
⇒ 0.81 = r × 27
⇒ r = 0.81/27 = 0.03 m = 3 cm
Therefore the radius of the circle is 0.03 m or 3 cm.
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