Question

A body moves in a circular path with a constant angular acceleration 5rad/s?. Then what is the angular
velocity of the body after 5 sec.(Initially body isat rest)

Answer 1

Answer: Angular velo after 5 sec is ω = 25 rad/s

Explanation:

Given :

angular accln α = 5 rad/s

Initial angular velo ω₀ = 0   [ ∵ rest]

Angular velo after 5 s is

ω = ω₀ + αt

   = 0 + 5 x 5

   = 25  rad /s

   

Answer 2

Answer:

The correct answer will be -

The angular velocity after 5 sec will be 25 rad/s.

Explanation:

We are given

• There is a body moving in a circular path
• It has a constant angular acceleration of 5 rad/s
• The body was initially at rest

We have to calculate its angular velocity after 5 sec

Angular acceleration is denoted as - $\alpha$

Angular velocity is denoted as - $\omega$

Now we know that the angular acceleration is the rate of change of the angular velocity.

$\alpha = \frac{\Delta \omega}{\Delta t}$

Now given,

$\omega_0 = \\\omega_t = ?\\\alpha = 5 \ rad/s^2\\t = 5\ sec$

Calculating angular velocity -

$\frac{\omega_t - \omega_0}{t-0} = \alpha\\\\\frac{\omega_t}{5} = 5\\\\\omega_t = 25 \ rad/s$

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