a body moves in a straight line along x axis . Its distance from the origin is given by x= 8t-3t^2 where x is in metres and t is in second . find the average velocity from t=0 to t=4 and find the instantaneous velocity of the particle at t= 2 seconds
Answers
Answered by
16
......................
Attachments:
Answered by
39
Here's your answer.
Firstly, average velocity.
Average velocity is calculated by dividing the total displacement travelled by the total time taken.
Here, the time is 4 seconds.
At t = 4 s, x = 8×4-3×4² = 32-48 = -16 m
So avg. velocity = -16/4 = -4 m/s
Instantaneous velocity is calculated by differentiation of the given function of displacement with respect to time.
So d/dt (8t-3t²) = 8-6t
8-6t is the function of velocity with respect to time.
At t = 2 s, v = 8-6×2 = 8-12 = -4 m/s
Firstly, average velocity.
Average velocity is calculated by dividing the total displacement travelled by the total time taken.
Here, the time is 4 seconds.
At t = 4 s, x = 8×4-3×4² = 32-48 = -16 m
So avg. velocity = -16/4 = -4 m/s
Instantaneous velocity is calculated by differentiation of the given function of displacement with respect to time.
So d/dt (8t-3t²) = 8-6t
8-6t is the function of velocity with respect to time.
At t = 2 s, v = 8-6×2 = 8-12 = -4 m/s
Similar questions