Question

A body moves in a straight line along x axis,its distance from the origin is given by the the equation x=8t-3t2 ,wgere x is in metre and t in seconds.Find the average velociyt in the time interval from t=0 and t=1s and in interval from t=0 and t=4s.

Answer 1

Answer:

x=5t − t2v = dx/dt = 5−2t average speed = ∫20vdt ∫20dt= ∫20(5−2t)dt ∫20dt=[5t − t2]202=(6/2) = 3m/sx=5t - t2v = dx/dt = 5-2t average speed = ∫02vdt ∫02dt= ∫02(5-2t)dt ∫02dt=5t - t2202=(6/2) = 3m/s

Answer 2

Explanation:

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