A body moves in a straight line along x-axis its distance from the origin is given {x=8t-3t^2} unit of x is meter and the unit of t is second:
find the average velocity in the interval
1)t=0 to t=1
2)t=0 to t=4
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Answer:
Given: y=8t−3t ^2
Average speed = total distance/total time
Total distance =8(1)−3(1 ^2 )=5 m
Total time =1 sec
⇒Average speed = 5/1
=5 m/s
Explanation:
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