Question

A body moves in a straight line with a uniform acceleration. If the initial velocity of the body is 5 m/s and the velocity after 10 s is 15 m/s, find the acceleration of the body and the distance

Answer 1

Answer:Suppose the acceleration is a then using the second equation of motion, s=ut+  2 1  at  2

 and putting t=2sec and u=10m/s  

we get 20=10×2+a×2

or a=0 that is uniform motion.

Explanation:

Answer 2

Initial velocity of body=u=5m/s

Final velocity of body=v=15m/s

time taken=t=10s

we know that

v=u+ at. (here a = acceleration)

15=5+10a

15-5=10a

10=10a

or a=1

thus the acceleration is 1m/s^2

now

v^2-u^2=2as. (here s =distance)

(15)^2-(5)^2=2×1×s

225-25=2s

200=2s

s=100m

thus distance=100m