Question

a body moves in a straight line with a uniform acceleration . If the initial velocity of a body is 5 m/s and velocity after 10 s is 15 m/s , find the acceleration and the distance covered by the body in this time interval

Answer 1

Answer- Let the acceleration of the body= a

Initial velocity (u)= 5 m/s

Final velocity (v)= 15 m/s

Time (t)= 10 s

a= (v-u)/t

= (15-5)/10

= 10/10

Therefore, acceleration = 1 m/s²

Let distance = s

By using 2nd equation of motion, s= $\frac{1}{2}$ at² + ut

s= $\frac{1}{2}$ × 1 × (10)² + 5 × 10

= $\frac{1}{2}$ × 100 + 50

= 50 + 50

Therefore, distance = 100 m

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