A body moves in a straight line with speed V1 and V2 for distance X1 and X2 . X1 and X2 are in the ratio 1 : 2 .Find the average speed.
Answers
Answer:
Displacement during the velocity v
1
will be x
1
=v
1
t
Displacement during the velocity v
2
will be x
2
=v
2
t
Average velocity will be
time
Displacement
=
t+t
x
1
+x
2
=
2t
v
1
t+v
2
t
=
2
v
1
+v
2
Option A is correct.
Answer: The answer is 3v1v2/v2=2v1
Explanation: A body moves in a straight line with speeds v₁ and v₂ for distances x₁ and x₂. x₁ and x₂ are in the ratio of 1 : 2.
To find the average speed.
Solution: we know, average speed = total distance/total time.
case 1 : time , t₁ = distance/speed = x₁/v₁
case 2 : time, t₂ = distance/speed = x₂/v₂
so, average speed = (x₁ + x₂)/(t₁ + t₂)
= (x₁ + x₂)/(x₁/v₁ + x₂/v₂)
a/c to question, x₁/x₂ = 1/2
= (x₁ + 2x₁)/(x₁/v₁ + 2x₁/v₂)
= 3/(1/v₁ + 2/v₂)
= 3v₁v₂/(v₂ + 2v₁)
Therefore the average speed of the body is 3v₁v₂/(v₂ + 2v₁)
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