a body moves in such a way that displacement is directly proportional to the cube of the time elapsed, then the motion is
1)uniform motion
2)uniform acceleration
3)non uniform acceleration
4)any of the above is possible
Answers
According to the question,
x ∝ t³
differentiating distance we get velocity
dx/dt =3t²
v ∝ t²
Differentiating velocity we get acceleration
dv/dt = 2t
a ∝ t
Here, acceleration depends on time
Therefore the motion will be non-uniform acceleration, as the acceleration will keep changing as time will change.
Given :
A body moves in such a way that displacement is directly proportional to the cube of the time elapsed,
To Find : the motion is
1)uniform motion
2)uniform acceleration
3)non uniform acceleration
4)any of the above is possible
Solution:
v = ds/dt
a = dv/dt = d²s/dt²
a = acceleration
v = velocity
s = displacement
t = time
s ∝ t³
=> s = kt³ k is a constnt
v = ds/dt = 3kt²
a = dv/dt = d²s/dt² = 6kt
Hence a ∝ t
a is proportional to t
Hence a is not constant , it varies with time
so non uniform acceleration is the correct answer
option 2) is correct answer
uniform motion : Velocity is constant
uniform acceleration : Velocity increased at constant rate. Acceleration is constant
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