Physics, asked by nlramesh71, 6 hours ago

a body moves in such a way that displacement is directly proportional to the cube of the time elapsed, then the motion is
1)uniform motion
2)uniform acceleration
3)non uniform acceleration
4)any of the above is possible

Answers

Answered by prachibarapatre
0

According to the question,  

x ∝ t³

differentiating distance we get velocity

dx/dt =3t²

 v ∝ t²

Differentiating velocity we get acceleration

dv/dt = 2t

a ∝ t

Here, acceleration depends on time

Therefore the motion will be non-uniform acceleration, as the acceleration will keep changing as time will change.

Answered by amitnrw
0

Given :

A body moves in such a way that displacement is directly proportional to the cube of the time elapsed,

To Find :  the motion is

1)uniform motion

2)uniform acceleration

3)non uniform acceleration

4)any of the above is possible

Solution:

v = ds/dt

a = dv/dt = d²s/dt²

a = acceleration

v = velocity

s = displacement

t = time

s ∝ t³

=> s = kt³     k is a constnt

v = ds/dt  = 3kt²

a = dv/dt = d²s/dt²  = 6kt

Hence a ∝ t

a is proportional to t

Hence a is not constant , it varies with time

so non uniform acceleration  is the correct answer

option 2) is correct answer

uniform motion : Velocity is constant

uniform acceleration : Velocity increased at constant rate.  Acceleration is constant

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