Question

a body moves in such a way that the displacements 12m towards east 5m towards north and 9m vetically upwards.​

Answer 1

Explanation:

=[−1256]=(−12)2+52+62−−−−−−−−−−−−−√=205−−−√≈14.32 ms→=[−1256]|s→|=(−12)2+52+62=205≈14.32 m

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Answer 2

Answer:

To find the magnitude of displacement..

1) consider the axis, it follows..

=> 12 m on x - axis

=> 5 m on y - axis

=> 9 m on z - axis.

Now since the angle in each case made is 90° with other respective axis.

So..

Magnitude of displacement will be

\begin{gathered} = > |a| = \bf\sqrt{ {x}^{2} + {y}^{2} + {z}^{2} } \\ \\ = > |a| = \sqrt{ {12}^{2} + {9}^{2} + {5}^{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{144 + 81 + 25} = \sqrt{250} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 \sqrt{10} \: \: m\end{gathered}

=>∣a∣=

x

2

+y

2

+z

2

=>∣a∣=

12

2

+9

2

+5

2

=

144+81+25

=

250

=5

10

m

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