Question

A body moves over three-quarters of a circle of radius"r". What is the magnitude of its displacement​

Answer 1

Answer:

Explanation:

Easy,

Imagine this problem as a clock,

The hour hand and the minute hand are at 12.

Let's imagine that the hour hand remains intact while the minute hand completes 3 quarters and reaches 9.

The angle between the hour hand and minute hand is 90° (for magnitude only).

So by applying Pythagoras theorem,

Displacement= √(r^2 + r^2))

Which comes out to be r√2.

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Answer 2

Answer:

Just hinting

points are on the circumference of a circle of radius r, and are separated on that circumference by one quarter of a circle, or 90 degrees. Therefore the magnitude of the displacement is r multiplied by the square root of 2, or approximately 1.4142 r.

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