Question

a body moves towards North for 5 m then takes sharp left turn and moves for another 12 m. if the total time taken by the body for this journey is 5s, then its average velocity is?? ​

Answer 1

Given:

A body moves towards North for 5 m then takes sharp left turn and moves for another 12 m.

To find:

Average velocity if time taken is 5 sec ?

Calculation:

First of all, let's find the displacement :

Using Pythagoras' Theorem:

$d = \sqrt{ {5}^{2} + {12}^{2} } = \sqrt{169} = 13 \: m$

Now, average velocity will be :

$\therefore \: avg. \: v = \dfrac{d}{t}$

$\implies\: avg. \: v = \dfrac{13}{5}$

$\implies\: avg. \: v = 2.6 \: m {s }^{ - 1}$

So, average velocity is 2.6 m/s.

Answer 2

by using Pythagoras theorem,

d = √[(5)² + (12)²]

= √(25 + 144)

= √169

= 13 m

then,

Average velocity = d/t

= 13/5

= 2.6 m/s