a body moves velocity of 10m/s after some time final velocity of body 30m/s travels 100m distance obtain acceleration
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HEY!!
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In order to answer this question, we must apply newton's first equation of motion
v = u + at
Where v is the final velocity in m/s, which is we shall attempt to find,
u is the initial velocity in m/s, given in the question as 20m/s
a is the acceleration of the body in m/s2, in the question, it is indicated to be 4m/s2
t is the time in seconds, from the question, it is 4s.
v = 20 + 4*4
v = 20 + 16 = 36m/s
As for the distance, either the second or third equation of motion can be used.
Using the second equation,
s (distance) = u*t + 0.5*a*(t^2)
s = 20*4 + 0.5*4*(4*4)
s = 80 + 32 = 112m
Using the third equation of motion,
v2 = u2 + 2as
36^2 = 20^2 + 2*4*s
1296 = 400 + 8 * s
8*s = 1296 - 400 = 896
s = 896/8 = 112m
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