Question

A body moves with 20m/s for 1min and after that it's velocity starts decreasing uniformly and comes to rest in 1min find the total distance covered and average speed.​

Answer 1

u= 20 m/s

t= 1 min =60 sec

Body moves for 60 sec by speed of 20 m/s

therefore, distance = 20 * 60 = 1200m = S1

Retardation,

    v= u-at      (here v=0)

   at=u

   60a = 20

   a = 1/3m /s^2

S2= ut + 1/2 at^2

since, acceleration is going negative

therefore ,

S2= ut -1/2 at^2

   = 20*60 - 1/2 * 1/3 * (60^2)  

    = 1200 - 1/6 * 3600

   = 1200-3600/6

    =1200 - 600

    = 600m

therefore,

total distance = S1+S2= 1200 + 600 = 1800m

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