a body moves with a constant acceleration Travels a distance 3 metre and 8 metre respectively in one second and two second calculate the initial velocity and acceleration of the body
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Distance(s1) = 3m
Time taken (t1) to travel 3 m =1 sec
Distance(s2) = 8m
Time taken (t2) to travel 8 m =2 sec
s = ut + 1/2 a. t2
s1 = ut1 + 1/2 a. t12
3 = u . 1 + 1/2 .a . 12
3 = u + a/2 ------- 1
s2 = ut2 + 1/2 a. t22
8 = u . 2 + 1/2 .a . 22
8 = 2u + 2a
8/2 = (2u + 2a)/2
4 = u + a ---------2
Subracting Eqn. 1 from Eqn. 2 (Eqn. 2 - Eqn. 1)
4 - 3 = (u + a) - (u + a/2)
1 = u + a - u - a/2
1 = a - a/2
1 = (2a - a)/2
1 = a /2
a = 2 m/s2
Initial velocity (u)= 2 m/s
Acceleration (a) = 2 m/s2
Mark Brainlieast....
DMani3:
Thanks for mark Brainlieast
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