Question

A body moves with an acceleration a = 6t. If it velocity at t=0 is 3 ms-1, express its velocity as a function of time.

Answer 1

Answer:

This problem pertains to motion along a straight line, starting with some initial velocity u = 0.5 m/s; and having an uniform acceleration a = +0.2 m/s². We are required to find its velocity after 4s and the distance covered by the body in that time.

To get the velocity after 4s, use the relation;

v = u + a t, where v is the velocity of the particle after a time t, when the particle had a velocity u at t=0 s, and an uniform acceleration = a.

Substituting the values for u, a and t =4s, we get

v = 0.5 m/s + 0.2 (m/s²) × 4 s = 0.5 m/s + 0.2 (m/s²) × 4 s = 0.5 m/s + 0.8 m/s = 1.3 m/s