A body moves with an initial velocity 2m/s.It gains an acceleration of 6 m/s²in a second.The displacement is
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Explanation:
The total distance travelled is =625m
The initial velocity is u = 0ms−1
The acceleration is a =10ms−2
The time is t=5s
Apply the equation of motion v=u+a t
The velocity is v = 0 + 10⋅5 = 50ms−1
The distance travelled in the first 5s is
s=ut + 12 at2 = 0⋅5 + 12⋅10⋅52 = 125m
The distance travelled in the following
10
s
is
s
1
=
v
t
1
=
50
⋅
10
=
500
m
The total distance travelled is
d
=
s
+
s
1
=
125
+
500
=
625
m
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