Question

a body moves with an initial velocity of 2 m per s and uniform acceleration of 3 m per sec square .calculate the velocity when it travelled a distance of 77m​

Answer 1

Answer:

So here:initial velocity (U)=10 m/s, Final velocity(V)=?, Acceleration(a)=m/s^2, Time(t)=4 seconds.

Therefore putting it in the equation: V=U+at, we get

V=10+2*4= 18

i.e. the final velocity is 18 m/s.

HOPE IT HELPS YOU

Answer 2

Answer:

you have given values as:

u=2m/s

a=3m/s square

s=77m

put these values in the given formula I.E

V^2=u^2+2as

Step-by-step explanation:

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