Question

a body moves with an initial velocity of 2 metre per second and uniform acceleration of 0.4 M per second square calculate the velocity of the 12 seconds and distance travelled in this time​

Answer 1

Explanation:

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so simple question

Answer 2

Explanation:

We have ,

u=2metre

a=0.4m/s^2,and , t=12seconds

We know that ,

v=u+at ( first equation of motion)

putting the values of u and at we get ,

v=2+(0.4*12)m/s

v=(2+4.8)m/s

v=6.8m/s

and , s=ut+1/2at^2

s=(2*12)+1/2(0.4*144)

s=24+1/2*57.6

s=24+23.8

s=47.8metres